The simplest approach is to check every single point. Compute the distance from the user's location to every restaurant in the database, keep the ones that are close enough, and throw away the rest.
# devtools = true # default
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描述：给定链表 head，对于每个节点，查找其右侧第一个值严格大于它的节点。返回整数数组 answer，answer[i] 为第 i 个节点的下一个更大节点值；若无，则为 0。
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